thrust::exclusive_scan_by_key
Defined in thrust/scan.h
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template<typename DerivedPolicy, typename InputIterator1, typename InputIterator2, typename OutputIterator>
OutputIterator thrust::exclusive_scan_by_key(const thrust::detail::execution_policy_base<DerivedPolicy> &exec, InputIterator1 first1, InputIterator1 last1, InputIterator2 first2, OutputIterator result) exclusive_scan_by_keycomputes an exclusive segmented prefixThis version of
exclusive_scan_by_keyuses the value0to initialize the exclusive scan operation.This version of
exclusive_scan_by_keyassumesplusas the associative operator used to perform the prefix sum. When the input and output sequences are the same, the scan is performed in-place.This version of
exclusive_scan_by_keyassumesequal_toas the binary predicate used to compare adjacent keys. Specifically, consecutive iteratorsiandi+1in the range[first1, last1belong to the same segment if*i == *(i+1), and belong to different segments otherwise.Results are not deterministic for pseudo-associative operators (e.g., addition of floating-point types). Results for pseudo-associative operators may vary from run to run.
Refer to the most general form of
exclusive_scan_by_keyfor additional details.The algorithm’s execution is parallelized as determined by
exec.The following code snippet demonstrates how to use
exclusive_scan_by_keyusing thethrust::hostexecution policy for parallelization:#include <thrust/scan.h> #include <thrust/execution_policy.h> ... int keys[10] = {0, 0, 0, 1, 1, 2, 3, 3, 3, 3}; int vals[10] = {1, 1, 1, 1, 1, 1, 1, 1, 1, 1}; thrust::exclusive_scan_by_key(thrust::host, key, key + 10, vals, vals); // in-place scan // vals is now {0, 1, 2, 0, 1, 0, 0, 1, 2, 3};
See also
exclusive_scan
- Parameters
exec – The execution policy to use for parallelization.
first1 – The beginning of the key sequence.
last1 – The end of the key sequence.
first2 – The beginning of the input value sequence.
result – The beginning of the output value sequence.
- Pre
first1may equalresultbut the range[first1, last1)and the range[result, result + (last1 - first1))shall not overlap otherwise.- Pre
first2may equalresultbut the range[first2, first2 + (last1 - first1)and the range[result, result + (last1 - first1))shall not overlap otherwise.