thrust::copy_n

Defined in thrust/copy.h

template<typename InputIterator, typename Size, typename OutputIterator> OutputIterator thrust::copy_n(InputIterator first, Size n, OutputIterator result)

copy_n copies elements from the range [first, first + n) to the range [result, result + n). That is, it performs the assignments *result = *first, *(result + 1) = *(first + 1), and so on. Generally, for every integer i from 0 to n, copy performs the assignment *(result

i) = *(first + i). Unlike std::copy_n, copy_n offers no guarantee on order of operation. As a result, calling copy_n with overlapping source and destination ranges has undefined behavior.

The return value is result + n.

The following code snippet demonstrates how to use copy to copy from one range to another.

#include <thrust/copy.h>
#include <thrust/device_vector.h>
...
size_t n = 100;
thrust::device_vector<int> vec0(n);
thrust::device_vector<int> vec1(n);
...
thrust::copy_n(vec0.begin(), n, vec1.begin());

// vec1 is now a copy of vec0